Vi\u1ec7c lu\u1eadn gi\u1ea3i nh\u1eefng con s\u1ed1, nh\u1eefng hi\u1ec7n t\u01b0\u1ee3ng ho\u1eb7c gi\u1ea5c m\u01a1 chi\u00eam bao l\u00e0 c\u1ea3 m\u1ed9t ngh\u1ec7 thu\u1eadt \u0111\u00f2i h\u1ecfi \u00f3c quan s\u00e1t v\u00e0 s\u1ef1 tinh t\u1ebf trong nh\u1eadn x\u00e9t c\u1ee7a ng\u01b0\u1eddi lu\u1eadn gi\u1ea3i. Do \u0111\u00f3 ch\u01a1i l\u00f4 \u0111\u1ec1 t\u01b0\u1edfng d\u1ec5 m\u00e0 kh\u00f3 \u0111\u1ea5y c\u00e1c b\u1ea1n. N\u1ebfu b\u1ea1n \u0111ang t\u00f2 m\u00f2 v\u1ec1 l\u00f4 \u0111\u1ec1 l\u00e0 g\u00ec v\u00e0 mu\u1ed1n t\u00ecm hi\u1ec3u nh\u1eefng kh\u00e1i ni\u1ec7m xung quanh l\u00f4 \u0111\u1ec1 th\u00ec h\u00e3y \u0111\u1ecdc b\u00e0i vi\u1ebft sau nh\u00e9!<\/p>\n
M\u1ee5c l\u1ee5c b\u00e0i vi\u1ebft<\/p>\n
- \n
- 1. L\u00f4 \u0111\u1ec1 (s\u1ed1 \u0111\u1ec1) l\u00e0 g\u00ec?<\/li>\n
- 2. \u0110\u00e1nh l\u00f4 l\u00e0 g\u00ec?<\/li>\n
- 3. \u0110\u00e1nh \u0111\u1ec1 l\u00e0 g\u00ec?<\/li>\n
- 4. So s\u00e1nh L\u00f4 \u0111\u1ec1 mi\u1ec1n B\u1eafc v\u00e0 l\u00f4 \u0111\u1ec1 mi\u1ec1n Nam\n
- \n
- 4.1.\u0110\u00e1nh s\u1ed1 \u0111\u1ec1 ki\u1ec3u mi\u1ec1n Nam l\u00e0 g\u00ec?<\/li>\n
- 4.2.\u0110\u00e1nh l\u00f4 \u0111\u1ec1 ki\u1ec3u mi\u1ec1n B\u1eafc l\u00e0 g\u00ec?<\/li>\n<\/ul>\n<\/li>\n
- 5. Ch\u01a1i l\u00f4 \u0111\u1ec1 l\u00e0 t\u1ed1t hay x\u1ea5u, c\u00f3 ph\u1ea1m ph\u00e1p kh\u00f4ng?<\/li>\n
- 6. L\u1eddi khuy\u00ean cho c\u00e1c d\u00e2n ch\u01a1i<\/li>\n<\/ul>\n<\/div>\n
<\/span>L\u00f4 \u0111\u1ec1 (s\u1ed1 \u0111\u1ec1) l\u00e0 g\u00ec?<\/h2>\n
\u1ede Vi\u1ec7t Nam, x\u1ed5 s\u1ed1 do nh\u00e0 n\u01b0\u1edbc t\u1ed5 ch\u1ee9c t\u1ed5ng c\u1ed9ng 27 l\u1ea7n x\u1ed5, l\u1ea7n \u0111\u1ea7u x\u1ed5 1 l\u1ed3ng c\u1ea7u, l\u1ea7n 2 x\u1ed5 2 l\u1ed3ng c\u1ea7u, l\u1ea7n 3 x\u1ed5 6 l\u1ed3ng c\u1ea7u, l\u1ea7n 4 x\u1ed5 4 l\u1ed3ng c\u1ea7u, l\u1ea7n 5 x\u1ed5 6 l\u1ed3ng c\u1ea7u, l\u1ea7n 6 x\u1ed5 3 l\u1ed3ng c\u1ea7u, l\u1ea7n 7 x\u1ed5 4 l\u1ed3ng c\u1ea7u. Tr\u00f2 ch\u01a1i l\u00f4 \u0111\u1ec1 n\u00e0y d\u1ef1a v\u00e0o hai con s\u1ed1 cu\u1ed1i c\u1ee7a t\u1ea5t c\u1ea3 c\u00e1c gi\u1ea3i l\u00e0m gi\u1ea3i th\u01b0\u1edfng, v\u1edbi gi\u1ea3i \u0111\u1eb7c bi\u1ec7t g\u1ecdi l\u00e0 \u201c\u0111\u1ec1\u201d, nh\u1eefng gi\u1ea3i c\u00f2n l\u1ea1i g\u1ecdi l\u00e0 \u201cl\u00f4\u201d. T\u00f9y theo th\u1eddi \u0111i\u1ec3m s\u1ebd c\u00f3 nh\u1eefng h\u00ecnh th\u1ee9c ch\u01a1i kh\u00e1c nhau nh\u01b0 \u0111\u00e1nh l\u00f4 v\u1ec1 \u0111\u1ec1 v\u1eabn t\u00ednh, \u0111\u00e1nh \u0111\u1ea7u \u0111u\u00f4i, 3 c\u00e0ng, 4 c\u00e0ng..<\/p>\n
<\/span>\u0110\u00e1nh l\u00f4 l\u00e0 g\u00ec?<\/h2>\n
<\/p>\n
Nh\u00ecn k\u1ebft qu\u1ea3 x\u1ed5 s\u1ed1 b\u00ean tr\u00ean, ta th\u1ea5y t\u1ea5t c\u1ea3 c\u00f3 8 gi\u1ea3i (c\u1ea3 \u0111\u1eb7c bi\u1ec7t), g\u1ed3m c\u00f3 27 s\u1ed1.<\/p>\n
\u0110\u00e1nh l\u00f4 l\u00e0 c\u00e1c b\u1ea1n d\u1ef1 \u0111o\u00e1n 2 con s\u1ed1 cu\u1ed1i c\u00f9ng c\u1ee7a t\u1ea5t c\u1ea3 c\u00e1c gi\u1ea3i (Ch\u1ec9 c\u1ea7n trong 27 s\u1ed1 m\u00e0 2 s\u1ed1 cu\u1ed1i c\u1ee7a 27 gi\u1ea3i \u0111\u00f3 c\u00f3 2 s\u1ed1 cu\u1ed1i b\u1ea1n d\u1ef1 \u0111o\u00e1n l\u00e0 b\u1ea1n tr\u00fang l\u00f4)<\/p>\n
V\u00ed d\u1ee5 1: M\u00ecnh \u0111\u00e1nh l\u00f4 28: 1 \u0111i\u1ec3m = 23k (1 \u0111i\u1ec3m l\u00f4 mi\u1ec1n b\u1eafc t\u00ednh 23k).<\/p>\n
V\u00ec k\u1ebft qu\u1ea3 x\u1ed5 s\u1ed1 ng\u00e0y hum \u0111\u00f3 c\u00f3 s\u1ed1 5028 n\u00ean m\u00ecnh s\u1ebd tr\u00fang, m\u00ecnh s\u1ebd \u0111\u01b0\u1ee3c 80k ( 1 \u0111i\u1ec3m =23k tr\u00fang 80k)<\/p>\n
V\u00ed d\u1ee5 2: M\u00ecnh \u0111\u00e1nh l\u00f4 90: 1 \u0111i\u1ec3m = 23k<\/p>\n
V\u00ec k\u1ebft qu\u1ea3 x\u1ed5 s\u1ed1 c\u00f3 2 gi\u1ea3i c\u00f3 s\u1ed1 cu\u00f4i l\u00e0 90 l\u00e0 2690 v\u00e0 90 n\u00ean m\u00ecnh s\u1ebd \u0111\u01b0\u1ee3c 160k ( b\u1eafn l\u00f4 2 ph\u00e1t, t\u01b0\u01a1ng t\u1ef1 3 ph\u00e1t s\u1ebd nh\u00e2n 3 l\u00e0 240k)<\/p>\n
N\u1ebfu kh\u00f4ng tr\u00fang th\u00ec s\u1ebd m\u1ea5t ti\u1ec1n.<\/p>\n
<\/span>\u0110\u00e1nh \u0111\u1ec1 l\u00e0 g\u00ec?<\/h2>\n
\u0110\u00e1nh \u0111\u1ec1 l\u00e0 c\u00e1c b\u1ea1n d\u1ef1 \u0111o\u00e1n 2 con s\u1ed1 cu\u1ed1i c\u00f9ng c\u1ee7a gi\u1ea3i \u0111\u1eb7c bi\u1ec7t:<\/p>\n
V\u00ed d\u1ee5: M\u00ecnh d\u1ef1 \u0111o\u00e1n hum nay \u0111\u1ec1 v\u1ec1 21: 10k ( \u0110\u00e1nh \u0111\u1ec1 21: 10 ngh\u00e0n)<\/p>\n
N\u1ebfu k\u1ebft qu\u1ea3 h\u00f4m \u0111\u00f3 gi\u1ea3i \u0111\u1eb7c bi\u1ec7t v\u1ec1: 58421 l\u00e0 m\u00ecnh tr\u00fang \u0111\u1ec1. M\u00ecnh s\u1ebd \u0111\u01b0\u1ee3c 700k ( V\u00ec \u0111\u00e1nh \u0111\u1ec1 1 \u0103n 70, nhi\u1ec1u n\u01a1i \u0111\u00e1nh 10k th\u00e0nh 11k (khuy\u1ebfn m\u1ea1i) n\u00ean tr\u00fang s\u1ebd \u0111\u01b0\u1ee3c 770k)<\/p>\n
N\u1ebfu gi\u1ea3i \u0111\u1eb7c bi\u1ec7t kh\u00f4ng v\u1ec1 2 s\u1ed1 cu\u1ed1i l\u00e0 21 th\u00ec m\u00ecnh s\u1ebd m\u1ea5t s\u1ed1 ti\u1ec1n \u0111\u00f3.<\/p>\n
<\/span>So s\u00e1nh L\u00f4 \u0111\u1ec1 mi\u1ec1n B\u1eafc v\u00e0 l\u00f4 \u0111\u1ec1 mi\u1ec1n Nam<\/h2>\n
c\u00e1ch ch\u01a1i l\u00f4 \u0111\u1ec1 c\u1ee7a mi\u1ec1n B\u1eafc v\u00e0 mi\u1ec1n Nam c\u00f3 nhi\u1ec1u \u0111i\u1ec3m kh\u00e1c nhau n\u00ean trong b\u00e0i vi\u1ebft n\u00e0y Th\u1ea7n C\u01a1 ti\u00ean t\u1eed s\u1ebd gi\u1ea3i \u0111\u00e1p cho c\u00e1c b\u1ea1n chi ti\u1ebft t\u1eeb kh\u00e1i ni\u1ec7m \u0111\u1ebfn so s\u00e1nh s\u1ef1 kh\u00e1c nhau lu\u00f4n nh\u00e9! Yeah Homie!<\/p>\n
<\/span>\u0110\u00e1nh s\u1ed1 \u0111\u1ec1 ki\u1ec3u mi\u1ec1n Nam l\u00e0 g\u00ec?<\/h3>\n
L\u00f4 mi\u1ec1n nam l\u1ea5y t\u1eeb hai ch\u1eef s\u1edb cu\u1ed1i c\u00f9ng c\u1ee7a 18 gi\u1ea3i th\u01b0\u1edfng trong k\u1ebft qu\u1ea3 x\u1ed5 s\u1ed1. C\u00e1ch t\u00ednh c\u1ee5 th\u1ec3 nh\u01b0 sau:<\/p>\n
1 \u0111 = 16 k.<\/p>\n
N\u1ebfu c\u00f3 khuy\u1ebfn m\u00e3i th\u00ec 1 \u0111 = 15,5 k.<\/p>\n
N\u1ebfu quen bi\u1ebft th\u00ec 1 \u0111 = 15 k.<\/p>\n
N\u1ebfu tr\u00fang m\u1ed9t \u0111i\u1ec3m th\u00ec b\u1ea1n s\u1ebd \u0111\u01b0\u1ee3c 80 k.<\/p>\n
N\u1ebfu l\u00f4 v\u1ec1 2, 3 con c\u00f9ng m\u1ed9t l\u00fac (b\u1eafn 2, 3 ph\u00e1t) th\u00ec b\u1ea1n s\u1ebd tr\u00fang 80 x 2=160 k ho\u1eb7c 80 x 3= 240 k. C\u1ee9 bao nhi\u00eau con v\u1ec1 th\u00ec nh\u00e2n h\u1ec7 s\u1ed1 l\u00ean b\u1ea5y nhi\u00eau.<\/p>\n
<\/p>\n
<\/span>\u0110\u00e1nh l\u00f4 \u0111\u1ec1 ki\u1ec3u mi\u1ec1n B\u1eafc l\u00e0 g\u00ec?<\/h3>\n
Kh\u00e1c v\u1edbi x\u1ed5 s\u1ed1 mi\u1ec1n nam, x\u1ed5 s\u1ed1 ki\u1ebfn thi\u1ebft mi\u1ec1n b\u1eafc c\u00f3 27 gi\u1ea3i. L\u00f4 mi\u1ec1n b\u1eafc \u0111\u01b0\u1ee3c l\u1ea5y t\u1eeb 2 s\u1ed1 cu\u1ed1i c\u1ee7a 27 gi\u1ea3i trong x\u1ed5 s\u1ed1 ki\u1ebfn thi\u1ebft.<\/p>\n
\u0110i\u1ec3m l\u00f4 \u0111\u01b0\u1ee3c t\u00ednh nh\u01b0 sau: 1 \u0111 = 23 k.<\/p>\n
Nhi\u1ec1u n\u01a1i khuy\u1ebfn m\u1ea1i: 1 \u0111 = 22,5 k.<\/p>\n
C\u00f3 n\u01a1i quen bi\u1ebft th\u00ec cho ghi 1 \u0111 = 22 k.<\/p>\n
N\u1ebfu tr\u00fang 1 \u0111 th\u00ec s\u1ebd \u0103n 80 k.<\/p>\n
N\u1ebfu 1 l\u00f4 b\u1eafn 2, 3 ph\u00e1t th\u00ec c\u1ee9 th\u1ebf nh\u00e2n l\u00ean theo s\u1ed1 con v\u1ec1 t\u1ee9c l\u00e0 tr\u00fang 80 x 2 = 160 k ho\u1eb7c 80 x 3 = 240 k.<\/p>\n